2x + 5 - ( x - 7 ) = 18
|3−x|+2⋅|7−x| = 18
12−|5−x| = 2x+7
3x⋅|2x+3|−7x = x−8
2(x-3)-7=5+(2x-18)
2(x - 3) - 7 = 5 + (2x - 18)
⇔ 2x - 6 - 7 = 5 + 2x - 18
⇔ 2x - 2x = 5 - 18 + 6 + 7
⇔ 0x = 0 (luôn đúng với mọi x)
Vậy S = R
2x+3x=57:5
7.(42- x) = 53+134
X+18÷32=5×42
1 tìm x thuộc Z
-2x-40=(5-x)-(-15+60)
2.(x-5)-3(x+7)=14
-7.(5-x)-2(x-10)=15
x+18=2-2x
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
\(-2x-40=\left(5-x\right)-\left(-15+60\right)\)
\(\Leftrightarrow\)\(-2x-40=5-x+15-60\)
\(\Leftrightarrow\)\(-2x-40=-x-40\)
\(\Leftrightarrow\)\(-2x+x=40-40\)
\(\Leftrightarrow\)\(x=0\)
Vậy....
\(x+18=2-2x\)
\(2x+x=2-18\)
\(3x=-20\)
\(x=-20:3\)
\(x=\frac{-20}{3}\)
tìm x:
a, (2x-5)^3=216
b, 2x-3 chia hết cho x+4( với x thuộc z)
c,|x-18|-2x+14=47
d,1 phần 6+ 5 phần 6:x = 7 phần12
a) Ta có: \(\left(2x-5\right)^3=216\)
\(\Leftrightarrow2x-5=6\)
\(\Leftrightarrow2x=11\)
hay \(x=\dfrac{11}{2}\)
b) Ta có: \(2x-3⋮x+4\)
\(\Leftrightarrow-11⋮x+4\)
\(\Leftrightarrow x+4\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{-3;-5;7;-15\right\}\)
Alo, sugeni two wai phem. Si ga no, you woo be the me that nas te, ai gi da
a)5. ( x + 35 ) = 515
b) (x+7):3=14c) 72:(x–15)=8
d) 19+(x+23)=50
e) (18–x) + 23 =29
f) 56–(x+14)=22g) (2x +1)–7=14
h) 3. (x+1)–32=67i) 70–5. (x–3)=45
j) 200–8. (2x+7)=112
k) 123–(x+4). 5 =38
\(a,\Rightarrow x+35=103\\ \Rightarrow x=68\\ b,\Rightarrow x+7=42\\ \Rightarrow x=35\\ c,\Rightarrow x-15=9\\ \Rightarrow x=24\\ d,\Rightarrow x+23=31\\ \Rightarrow x=8\\ e,\Rightarrow18-x=6\\ \Rightarrow x=12\\ f,\Rightarrow x+14=34\\ \Rightarrow x=20\\ g,\Rightarrow2x+1=21\\ \Rightarrow x=11\\ h,\Rightarrow3\left(x+1\right)=99\\ \Rightarrow x+1=33\Rightarrow x=32\\ i,5\left(x-3\right)=25\\ \Rightarrow x-3=5\\ \Rightarrow x=8\\ j,\Rightarrow8\left(2x+7\right)=88\\ \Rightarrow2x+7=11\Rightarrow x=2\\ k,\Rightarrow5\left(x+4\right)=85\\ \Rightarrow x+4=17\\ \Rightarrow x=13\)
tìm x,biết
5.(x+7)-3.(2-x)
12(x-3)=5(x-1)+4
(-6).(x-7)+2(x+10)=x-18
7.(2x-1)-12(x-5)=3
|2x-1|=17
|8-3x|=14
5.(x+7)=3.(2-x)
=>5x+35=6-3x
=>5x+3x=6+41
=>8x=47
=>x=47:8=47/8
tìm x,biết
5(x+7)-3(2-x)
12(x-3)=5(x-1)+4
(-6).(x-7)+2(x+10)=x-18
7(2x-1)-12(x-5)=3
|2x-1|=17
|8-3x|=14
\(12\left(x-3\right)=5\left(x-1\right)+4\)
\(\Rightarrow12x-36=5x-5+4\)
\(\Rightarrow12x-5x=-5+4+36\)
\(\Rightarrow7x=35\)
\(\Rightarrow x=5\)
\(-6\left(x-7\right)+2\left(x+10\right)=x-18\)
\(-6x+42+2x+20=x-18\)
\(-6x+2x-x=-18-20-42\)
\(-5x=-80\)
\(x=16\)
\(7\left(2x-1\right)-12\left(x-5\right)=3\)
\(\Rightarrow14x-7-12x+60=3\)
\(\Rightarrow14x-12x=3-60+7\)
\(\Rightarrow2x=-50\)
\(\Rightarrow x=-25\)
\(\left|2x-1\right|=17\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=17\\2x-1=-17\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)
\(\left|8-3x\right|=14\)
\(\Leftrightarrow\orbr{\begin{cases}8-3x=14\\8-3x=-14\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{22}{3}\end{cases}}\)
X/7=Y/5 và 2x-y=-18
\(\frac{x}{7}=\frac{y}{5}=\frac{2x}{14}=\frac{2x-y}{14-5}=-\frac{18}{9}=-2\)
=>x=-14;y=-10
vậy x=-14;y=-10
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